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NTA has announced key dates for JEE Main 2026 Session 2 answer key (April 11) and results (April 20). Learn how to download, raise objections, and understand percentiles.
Are you one of the millions of students who recently appeared for the JEE Main 2026 Session 2 exam and are now eagerly awaiting your answer key and results? The National Testing Agency (NTA) has announced all the important dates you've been waiting for. These announcements will help students plan their future strategies.
The JEE Main 2026 Session 2 exam was successfully conducted from April 2nd to April 8th. Now that the exam is over, all eyes are on the answer key and the final results. Let's delve into these important announcements and what they mean for you.
NTA will release the JEE Main Session 2 answer key on April 11th. This is a crucial milestone for all students who wish to assess their performance. The answer key will be available online on NTA's official website jeemain.nta.nic.in.
Steps to Download JEE Main Answer Key:
As soon as the answer key is released, you can download it by following these simple steps:
After the answer key is released, if any student believes there is an error in an answer provided by NTA, they will get an opportunity to raise an objection. You can raise your objection within the stipulated time frame by paying a fee of Rs. 200 per question. This process ensures that all potential errors can be corrected before the results are declared.
A large number of students participated in the JEE Main Session 2 exam, reflecting their aspiration to gain admission to engineering colleges across the country. According to details shared by NTA, a total of 11.23 lakh students participated in the JEE Main Session 2 exam.
Looking at the detailed statistics:
These figures indicate the vastness of the examination and the huge number of students participating in it.
The JEE Main Session 2 results will be announced on April 20th. This date is crucial for the future of millions of students. The results will be prepared taking into account the final answer key, which will be made available along with the results.
After the declaration of results, students will be able to participate in the counseling process for admission to various NITs, IITs, and other Government Funded Technical Institutions (GFTIs) based on their percentile and rank. This is not just a score, but the next step towards your engineering dreams.
In JEE Main, NTA does not directly create ranks based on your raw marks. Instead, it looks at where you stand compared to other students in your shift. This is called percentile.
NTA uses a special mathematical formula for percentile calculation:
Percentile = (Number of students in your shift with score less than or equal to yours ÷ Total students in the shift) × 100
Suppose a total of 1,000 students appeared for the exam in your shift. If 950 students scored less than or equal to you, then your percentile will be calculated as follows:
(950 ÷ 1,000) × 100 = 95 Percentile
Since the JEE Main exam is conducted over several days and in different shifts, it is possible that the paper for one shift might be difficult and for another, easy. The normalization process ensures that no student is disadvantaged due to the difficulty or ease of the paper. It is a way to bring the scores of all shifts to a uniform level, ensuring a fair evaluation for all students.
Based on various coaching institutes and trends from previous sessions, the estimated figures for the April 8th shift could be as follows:
| Expected Score | Estimated Percentile | Expected All India Rank |
|---|---|---|
| 240-280+ | 99.9+ | 1-1,200 |
| 210-240 | 99.5-99.9 | 1,200-6,000 |
| 180-210 | 99.0-99.5 | 6,000-12,000 |
| 160-180 | 98.0-99.0 | 12,000-25,000 |
| 140-160 | 97.0-98.0 | 25,000-35,000 |
| 120-140 | 95.0-97.0 | 35,000-60,000 |
If a student scores approximately 80 marks, their percentile is expected to be between 89 and 91. At such a score, it might be challenging for General category students to get admission into top NITs or IITs. However, for OBC/EWS category students, this score could be helpful for qualifying for JEE Advanced. This indicates that cut-offs and admission possibilities differ based on category.
If you wish to gain admission to the Computer Science (CS) branch in the top-5 NITs of the country, your percentile should be between 99.7 and 99.9. This is a high target that requires excellent performance. To get into these prestigious institutions, students not only have to work hard but also prepare smartly.
Key Takeaway: To succeed in JEE Main, hard work alone is not enough; a smart study plan and the right guidance are equally important.
The JEE Main 2026 Session 2 results are going to be declared soon. Now is the time to consider your future strategy. Whether you are preparing for JEE Advanced or getting ready for the counseling process, PATAMDE is with you.
PATAMDE is India's AI-powered learning platform that helps you strengthen your preparation. Our smart study tools like the PATAMDE AI Quiz Generator can help you identify your weaknesses and work on them. With a personalized learning experience, you can give your preparation a new direction and achieve your goals.
To realize your dreams, making the right decision at the right time is crucial. Join PATAMDE and make your path to success easier!
PATAMDE Team
Content Team
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